user100000
Long

Bitcoin cycle duration

BITSTAMP:BTCUSD   Bitcoin / U.S. Dollar
I calculated BTC             has a 12.2 week +- 2.5 cycle duration (low to low). It is week 10 since the last cycle low. We have a couple of weeks to make a high (408?) and set a cycle low.
please note: the cycle average has to be continually updated whenever a new cycle low presents itself. it is 12.2 week cycle now, but it will fluctuate over time and should always be updated just like moving averages
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today may be a cycle low. week 10. it is within the +-2.5 window of 12.2 week cycle
ew analysis and cycles really work well together. cycle low + b wave retracement
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user100000 user100000
on second thought, i will "save" the cycle low label for wave (2)... this drop isn't horrific enough to deserve a cycle low label and doesn't stand out on the weekly chart. we have a another 4.7 weeks max to make a high (387) and drop violently (wave (2))
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Forgive me. I don't understand how a high of 408 is a cycle "low". Can you please explain?
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user100000 rivet.popper
I meant we have a couple of weeks to make a high (408) and later drop down for the cycle low all within a couple of weeks
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julia17 user100000
where do you expect low after movement to 408?
-2 Reply
user100000 julia17
"where do you expect low after movement to 408?"

the retracement could be shallow or deep; more likely deep especially after a diagonal. it could "crash" to 210 (wave 4); that is the worst case. it may also be shallow such as retracing 38.2%. too early to tell
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user100000 user100000
you can use cycles to time your trade. buy or add to your position on the coming cycle low. and don't forget about the +-2.5 week window
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rivet.popper user100000
So we are going to 408 in about 2 weeks and then down to around 210? What happened to the sustained wave up after the 408 high?
+1 Reply
user100000 rivet.popper
nothing has changed. after the correction of the diagonal wave (3) should kick in; that is your high energy wave. i remember you asked how long will the correction last. i replied approx 1/3 of the time it took to form the diagonal
+1 Reply
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