Market DNA Copper Cycle 3 Phase 1 of 4

Will the next phase be Phase 2 or 3? We are navigating the market to see what happens next.

Phase: 1
Date & Time: 2026-05-19 22:56 EST
Primary Entry M: 6.1478 $
Secondary Entry P(c): 5.917$
Mean Entry: (6.1478+5.917)/2=6.0324$
Trapezoid Time Duration: 24 Days
3th Triangle domain (%): 2 * 5.22% = 10.44%
Risk coefficient (R): 3
Risk domain (%) (D): (3th Triangle domain) *(Risk coefficient) = 10.44%*3 = 31.32 %
Hypothetical Capital: 100,000$
Contract Size: 10000 Unit
Expected Max Drawdown (%): 5%
Expected Max Drawdown $ (EMDD): 100,000 * 5% = 5,000
Expected Low Price: (1 – 31.32%) * 6.0324$ = 4.143$
Size: 5,000 / (6.0324 – 4.143) ~= 2646.34Unit
Position Size: Size/Contract Size = 2646.34 /10000 = 0.26
Each Trade Size = 0.26 /2 = 0.13

Targets:
T1 (Mirror / Lower Trapezoid): 6.2173$
T2 (Apex N): 6.4996 $
T3 (Trapezoid Top): 6.718$
Expected Profit by first entry and Exit at T3 for Scenario No 1:
(T3 - Entry M) * Contract Size * Each Trade Size = (6.718 -6.1478) *10000*0.13= 741.26$
Expected Total Profit for Scenario No 1: 741.26$
Expected Return % for Scenario No 1: 100*(741.26/100,000) = 0.74%
Expected Annual Return% for Scenario No 1: (0.74 %*365/24) =11.25%
Expected Profit by 2th entry and Exit at T2 for Scenario No 2:
(T3 - Entry M) * Contract Size * Each Trade Size = (6.718 -6.1478) *10000*0.13= 741.26$
(T2 - Entry P(c)) * Contract Size * Each Trade Size = (6.4996 -5.917) *10000*0.13= 757.38$
Expected Total Profit for Scenario No 2: 741.26+757.38=1,498.64$
Expected Return% for Scenario No 2: 100*(1,498.64/100,000) =1.49%
Expected Annual Return% for Scenario No 2: 1.49%*365/24=22.66%
Notes: P(c) may or may not be reached; both M and P(c) are Phase 1 only.

"Both trade sizes are calculated using the hypothetical capital, the investor’s maximum allowed drawdown, the 3rd Triangle Domain percentage, the Risk Coefficient, and the Contract Size."
TotalSize=(EMDD=5000)/(2*D*R*MeanPrice*ContractSize)